68x^2-26x-4=0

Solution for 68x^2-26x-4=0 equation:

68x^2-26x-4=0

a = 68; b = -26; c = -4;
Δ = b2-4ac
Δ = -262-4·68·(-4)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-42}{2*68}=\frac{-16}{136}
=-2/17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+42}{2*68}=\frac{68}{136}
=1/2
$